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AP - Calculus AB/BC:: Differentiation - Definition and Fundamental Properties

Created by Chat Robotics Community  ·  Updated 2026-08-30

Curriculum Overview

Topics & Key Concepts

Ap Calculus

Sample Flashcard Questions & Answers

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Question #1 Active Recall

Which limit expression correctly defines \(f'(a)\), the derivative of \(f\) at \(x=a\)?

- **A)** \(\lim_{h \to 0} \dfrac{f(a+h) - f(a)}{h}\)
- **B)** \(\lim_{h \to 0} \dfrac{f(a) - f(a+h)}{a}\)
- **C)** \(\lim_{h \to \infty} \dfrac{f(a+h)}{h}\)
- **D)** \(\dfrac{f(a+h) - f(a)}{h}\) for any fixed small \(h\)

Answer & Explanation:
**Answer: A)**

This difference-quotient limit is the formal definition of the derivative at a point, representing the limiting slope of secant lines as they approach the tangent line at \(a\).
Question #2 Active Recall

The alternate (equivalent) limit definition of \(f'(a)\) is:

- **A)** \(\lim_{x \to 0} \dfrac{f(x)}{x - a}\)
- **B)** \(\lim_{x \to a} f(x) - f(a)\)
- **C)** \(\lim_{x \to a} \dfrac{f(x) - f(a)}{x - a}\)
- **D)** \(\lim_{x \to a} \dfrac{f(a)}{x}\)

Answer & Explanation:
**Answer: C)**

Substituting \(x = a+h\) into the standard difference quotient and letting \(x \to a\) (equivalent to \(h \to 0\)) gives this algebraically equivalent form.
Question #3 Active Recall

Which of the following is NOT standard notation for the derivative of \(y = f(x)\)?

- **A)** \(y'\)
- **B)** \(\dfrac{dy}{dx}\)
- **C)** \(f'(x)\)
- **D)** \(\Delta y\)

Answer & Explanation:
**Answer: D)**

\(\Delta y\) denotes a finite change in \(y\) (used in difference quotients and approximations), not the derivative itself, which is a limiting rate of change.
Question #4 Active Recall

The derivative \(f'(a)\) is best interpreted as:

- **A)** The total change in \(f\) from \(0\) to \(a\)
- **B)** The average rate of change of \(f\) over \([a, a+1]\)
- **C)** The instantaneous rate of change of \(f\) at \(x=a\), i.e., the slope of the tangent line to the graph at that point
- **D)** The value of \(f\) at \(x=a\)

Answer & Explanation:
**Answer: C)**

The derivative at a point gives the instantaneous rate of change, geometrically the slope of the line tangent to the curve at that exact point.
Question #5 Active Recall

Using the Power Rule, find \(\dfrac{d}{dx}\left[x^5\right]\).

- **A)** \(x^4\)
- **B)** \(4x^5\)
- **C)** \(5x^4\)
- **D)** \(5x^5\)

Answer & Explanation:
**Answer: C)**

The Power Rule states \(\dfrac{d}{dx}[x^n] = nx^{n-1}\); with \(n=5\), this gives \(5x^4\).
Question #6 Active Recall

Find \(\dfrac{d}{dx}\left[x^{-3}\right]\).

- **A)** \(-3x^{-2}\)
- **B)** \(-3x^{-4}\)
- **C)** \(3x^{-4}\)
- **D)** \(-\dfrac{1}{3}x^{-4}\)

Answer & Explanation:
**Answer: B)**

The Power Rule applies to negative exponents too: \(n=-3\) gives \(-3x^{-3-1} = -3x^{-4}\).
Question #7 Active Recall

Find \(\dfrac{d}{dx}\left[\sqrt{x}\right]\) by rewriting \(\sqrt{x} = x^{1/2}\) and applying the Power Rule.

- **A)** \(\dfrac{1}{2}x^{-1/2} = \dfrac{1}{2\sqrt{x}}\)
- **B)** \(2x^{-1/2}\)
- **C)** \(\dfrac{1}{2}x^{1/2}\)
- **D)** \(\dfrac{1}{2}\)

Answer & Explanation:
**Answer: A)**

With \(n = 1/2\), the Power Rule gives \(\tfrac{1}{2}x^{-1/2}\), which can be rewritten as \(\dfrac{1}{2\sqrt{x}}\).
Question #8 Active Recall

What is \(\dfrac{d}{dx}[7]\) (the derivative of a constant)?

- **A)** \(0\)
- **B)** \(1\)
- **C)** Undefined
- **D)** \(7\)

Answer & Explanation:
**Answer: A)**

A constant function never changes, so its instantaneous rate of change (and hence derivative) is always \(0\), by the Constant Rule.

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